After the n th tick of damage received from fatigue, you will have received n(n+1)/2. If you have already received your p th fatigue tick, at the n th tick of fatigue, you will have received (n-p)(n+p+1)/2 more.
After the n th tick of damage received from fatigue, you will have received n(n+1)/2. If you have already received your p th fatigue tick, at the n th tick of fatigue, you will have received (n-p)(n+p+1)/2 more.
n= (n+1)?
Top deck in math
If u 1st turn: 1/25
*Genius*
Do you mean fatigue damage? If so, then yes, it's the number of failed draw attempts.
After the n th tick of damage received from fatigue, you will have received n(n+1)/2. If you have already received your p th fatigue tick, at the n th tick of fatigue, you will have received (n-p)(n+p+1)/2 more.
Gauss is proud of you
I could change the world, but it is not open sourced.