Legendary Paladin Card Revealed - Sir Finley of the Sands
As part of the Comic Con Legendary set, Gamereactor revealed a new Saviors of Uldum Legendary card for Paladin: Sir Finley of the Sands
This is just 1 of 4 Legendary Saviors of Uldum cards revealed for the League of Explorers, be sure to see the other 3:
Dinotamer Brann - Elise the Enlightened - Reno the Relicologist
Saviors of Uldum Expansion Guide
Learn more and see all the cards in our dedicated expansion guide.
look at that stat line!!! This biceps!
Did Sir Finley hit the gym?
I dont know why you are all Complaining. I realy like the card its a good option for aggro decks like the one mana sir finley was. I hope aggro will be playable again i cant see all the 30 minute Control warrior agains some other Control shit anymore. Thats why i stopped playing hearthstone for a while because personaly control meta is the least fun for me expecially when aggro is super weak right now like it was never before.
Dude, like you say there is no good aggro deck so there will definitely not be an aggro deck with No duplicates allowed in the new meta. So this card sucks or works with control never with aggro
^ this
i thought we been over powerfull starting effect blizzard
Bomb warrior gonna ruin all these new single style legendaries, has to be something coming to help them work.
All 4 Legendaries are DOA against Bomb Warrior
Unless we get a card: "destroy all duplicates in the deck"
Zero fun. Zero originality.
TANK UP CONTROL PALADIN NEW META
my body is ready
since hero paladin already got alternatif hero power from Sir Finley of the Sands, im pretty sure the paladin quest reward could be a weapon, isn't?
Typically each expansion has two different themes per class and one legendary for each.
For anyone who is interested, I did the math for how likely you are to get the one hero power you really want. Because you can never be offered the same discover option multiple times, the first choice has a 1/9 chance of being your desired power, second choice has a 1/8 chance, and your 3rd choice has a 1/7 chance. If you multiply the denominators together to find a single common denominator then you get 504. When you adjust your numerators accordingly you end up with 56/504, 63/504 and 72/504. The sum of these 3 probabilities is 191/504. Plug that into a calucalator and you get .37896.
TLDR: You have about a 38% chance of finding the exact hero power you are hoping for.
Not sure if it's a sarcastic comment...
That’s not how it works. It should be calculated as follows:
1-8/9(the chance of *not* being offered your desired hero power in the first card)*7/8(the chance of *not* being offered your desired hero power in the second card, given that it wasn’t offered in the first card)*6/7(similar logic)=1/3
You have a 33.3% chance of getting the hero power that you want.
Another easy way rather than having to do any math is just 3/9 (total revealed out of total available). Should be pretty intuitive for most people.
Here's some calculations for if you had more than 1 hero power that you're fine with.
One of 2 hero powers you want: 1-(7/9*6/8*5/7) = 58.3%
One of 3: 1-(6/9*5/8*4/7) = 76.2%
One of 4: 1-(5/9*4/8*3/7) = 88.1%
One of 5: 1-(4/9*3/8*2/7) = 95.2%
Yeah but you also have to consider that many decks would deem multiple hero powers viable. The old LoE Finley is a Staple in Wild Agrro decks, and they want Warlock the most, but Hunter is also very good.
Old Finley was super powerful and so will be this, if the Highlander deck works for Paladin.
You made all those counts to look smart and is still wrong, there's nothing complicated there. Since there are 9 hero powers and discover gives you 3 options, 3 out of 9 is 1/3 of chance of getting the one you want: 33.3% ~
You have 9 hp’s and 3 choices so 33,3% 🤔