So I was testing out a silly reno wildfire deck for the patch where I run double wildfire because It's the strongest card in the deck. I run a couple spell tutors and I was testing out how long it usually took for me to draw one of them playing against innkeeper.
The situation here was that both wildfires ended up as the last 2 cards in my deck (even with me playing ALL my spell tutors, including tortollan btw). What are the chances of not drawing A SINGLE COPY of my wildfires in a deck where there are no other duplicates? Is there anyway for me to find this out without spending too much time?
Simply math my friend, that i have no idea how to solve lmao.
It's easy to find out if you have 2 of every card in your deck, because then the chances of me not drawing wildfire once until they are the last two cards in my deck, excluding card tutors, are 0.690%. Now I have 2 wildfires but 1 of everything else, so this means that i have double the chances of drawing a wildfire everytime i draw a card and that's hard to figure out, unless i'm overcomplicating things.
Can someone good at maths calculate the chance of me opening 4 copies of the same common on one pack? Happened to me long ago in closed beta, none golden.
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So I was testing out a silly reno wildfire deck for the patch where I run double wildfire because It's the strongest card in the deck. I run a couple spell tutors and I was testing out how long it usually took for me to draw one of them playing against innkeeper.
The situation here was that both wildfires ended up as the last 2 cards in my deck (even with me playing ALL my spell tutors, including tortollan btw). What are the chances of not drawing A SINGLE COPY of my wildfires in a deck where there are no other duplicates? Is there anyway for me to find this out without spending too much time?
Simply math my friend, that i have no idea how to solve lmao.
It's easy to find out if you have 2 of every card in your deck, because then the chances of me not drawing wildfire once until they are the last two cards in my deck, excluding card tutors, are 0.690%. Now I have 2 wildfires but 1 of everything else, so this means that i have double the chances of drawing a wildfire everytime i draw a card and that's hard to figure out, unless i'm overcomplicating things.
Quick Google search and I found this:
Generally you care about your odds of having reno active on 6, they improve a bit with a hard mulligan for wildfire.
Can someone good at maths calculate the chance of me opening 4 copies of the same common on one pack? Happened to me long ago in closed beta, none golden.